Question

How many solutions are there to the equation below? 6x + 30 + 4x = 10(x + 3)

(A). 0
(B). Infinitely many
(C). 1

Answer 1

Hi there! The answer is B.

Let's solve this equation step by step!
$6x + 30 + 4x = 10(x + 3)$

First work out the parenthesis, which can for instance be done using rainbow technique.
$6x + 30 + 4x = 10x + 30$

Now collect terms.
$10x + 30 = 10x + 30$

We can now conclude that the left side of the equation exactly equals the right side. Therefore it doesn't matter whatever value of x we plug in into the eqiation, since the left and the right will always be the same (equal). Therefore, there are infinitely many solutions to this equation. The answer is B.

~ Hope this helps you!

Answer 2

In the equation $6x + 30 + 4x = 10(x + 3)$, the number of solutions are: (B). Infinitely many.

Given the following equation:

• $6x + 30 + 4x = 10(x + 3)$

To determine the number of solutions that are in the given equation:

First of all, we would open the bracket.

$6x + 30 + 4x = 10x + 30$

Next, we would rearrange the equation:

$10x + 30 = 10x + 30$

Since the equation on the left-hand side is equal to the equation on the right-hand side, we can conclude that this equation has infinitely many solutions because numerous value of x can be substituted into the equation.

Therefore, the equation can take on as many values of x as possible.

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