Question

How many liters of a 3.52 M K2SO4 solution are needed to provide 89.2 g of K2SO4

Answer 1

Molar mass K₂SO₄ = 174.259 g/mol

1 mole K₂SO₄ ------------> 174.259 g
? mole K₂SO₄ ------------> 89.2 g

number of mole:

n = m / molar mass

n = 89.2 / 174.259

n = 0.51188 moles of K₂SO₄

Molarity ( M ) = moles solute / liters solution

3.52 =  0,51188 / V

V = 0.51188 / 3.52

V = 0.1454 L

hope this helps!