The correct answer is option #1. x = -2 +/- 2i
We can find this by using the quadratic equation, which is written below.
[tex] \frac{-b +/- \sqrt{ b^{2} -4ac} }{2a} [/tex]
Now we know the a, b and c values by looking at the equation. a is always the number attached to x^2 (which is 1), b is always the number attached to x (which is 4) and c is the number with no variable (which is 8). So we can place them in in the appropriate spots in the equation.
[tex] \frac{-b +/- \sqrt{ b^{2} -4ac} }{2a} [/tex]
[tex] \frac{-4 +/- \sqrt{ 4^{2} -4(1)(8)} }{2(1)} [/tex]
[tex] \frac{-4 +/- \sqrt{ 16 - 32} }{2} [/tex]
[tex] \frac{-4 +/- \sqrt{ -16} }{2} [/tex]
[tex] \frac{-4 +/- 4i }{2} [/tex]
-2 +/- 2i