Solve x2 + 4x + 8 = 0. (2 points)



1. x equals negative 2 plus or minus 2 I
2. x equals negative 2 plus or minus 4 I
3. x equals negative 4 plus or minus 2 I
4. x equals negative 4 plus or minus 4 I

Respuesta :

The correct answer is option #1. x = -2 +/- 2i

We can find this by using the quadratic equation, which is written below. 

[tex] \frac{-b +/- \sqrt{ b^{2} -4ac} }{2a} [/tex]

Now we know the a, b and c values by looking at the equation. a is always the number attached to x^2 (which is 1), b is always the number attached to x (which is 4) and c is the number with no variable (which is 8). So we can place them in in the appropriate spots in the equation. 

[tex] \frac{-b +/- \sqrt{ b^{2} -4ac} }{2a} [/tex]

[tex] \frac{-4 +/- \sqrt{ 4^{2} -4(1)(8)} }{2(1)} [/tex]

[tex] \frac{-4 +/- \sqrt{ 16 - 32} }{2} [/tex]

[tex] \frac{-4 +/- \sqrt{ -16} }{2} [/tex]

[tex] \frac{-4 +/- 4i }{2} [/tex]

-2 +/- 2i

Answer:

x = -2 +/- 2i

(Took the test just now, hope this helps ! Good luck :) !  )


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