Respuesta :
According to Boyle's law, volume is inversely proportional to pressure. thus P=k/V
Therefore PV=k
P1V1=P2V2
In the question above,
P1=3.67atm
P2=1.94atm
V1=2.22L
V2=?
Thus substituting for the values in the gas equation;
3.67atm*2.22L=1.94atm*V2
V2=3.67atm*2.22L/1.94atm
=4.21L
Therefore PV=k
P1V1=P2V2
In the question above,
P1=3.67atm
P2=1.94atm
V1=2.22L
V2=?
Thus substituting for the values in the gas equation;
3.67atm*2.22L=1.94atm*V2
V2=3.67atm*2.22L/1.94atm
=4.21L
The final volume of the gas when the pressure is 1.94 atm is 4.20 L.
Given that:
The initial pressure of the gas = 3.67 atm
The initial volume of the gas = 2.22 L
The final volume of the gas = ???
The final pressure of the gas = 1.94 atm
According to Boyle's law, we know that the volume of the gas varies indirectly proportional to the pressure.
i.e.
[tex]\mathbf{V= \dfrac{k}{P}}[/tex]
k = PV
∴
P1V1 = P2V2....PnVn
Using the equation;
P1V1 = P2V2
V2 = P1V1/P2
V2 = (3.67 atm × 2.22 L) / 1.94 atm
V2 = 4.20 L
Therefore, we can conclude that the final volume of the gas when the pressure is 1.94 atm is 4.20 L.
Learn more about Boyle's Law here:
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