Question

What volume of a 0.33-m c12 h22 o11 solution can be diluted to prepare 25 ml of a solution with a concentration of 0.025 m?

Answer 1

Answer : When we are diluting a solution of $C_{12} H_{22} O_{11}$ from 0.33 m to 0.025 m of 25 ml we will need 1.89 ml of 0.33 m solution for the dilution.

Explanation : Using the formula $m _{1}V_{1}=m_{2} V_{2}$

we can calculate the $V_{1} = (25 X 0.025) / 0.33 = 1.89 mL$