Question

What are the factors of m2 – 12m + 20?

Answer 1

the factors of this trinominal would be
m-10 & m-2

Answer 2

Answer:

Factor of $m^{2}-12m+20$ is $=\left(m-2\right)\left(m-10\right)$

Step-by-step explanation:

We need to find the factors of $m^{2}-12m+20$

$\mathrm{Break\:the\:expression\:into\:groups}$

$=\left(m^2-2m\right)+\left(-10m+20\right)$

$\mathrm{Factor\:out\:}m\mathrm{\:from\:}m^2-2m\mathrm{:\quad }m\left(m-2\right)$

$\mathrm{Factor\:out\:}-10\mathrm{\:from\:}-10x+20\mathrm{:\quad }-10\left(m-2\right)$

$=m\left(m-2\right)-10\left(m-2\right)$

$=\left(m-2\right)\left(m-10\right)$

Hence, factor of $m^{2}-12m+20$ is $=\left(m-2\right)\left(m-10\right)$