Question

The wavelength of red light is given as 6.5 × 10-7 m. If another wave of an unknown type has a frequency of 5.3 × 1015 Hz. What is the relation between the wavelength of the unknown wave and red light? (note: c = 2.998 × 108 m/s) The wavelength of the unknown wave is less than the wavelength of red light. The wavelength of the wave is greater than the wavelength of red light. The wavelength of the wave is equal to the wavelength of red light. The wavelength of the wave is not related to the wavelength of red light.

Answer 1

The red light has a frequency of:

c = v X wavelength 
unknown wavelength = ? m 
v = frequency = 5.3 X 10^15 Hz 
so 2.998 X 10^8 = 5.3 X 10^15 X wavelength 
wavelength = 2.998 X 10^8 / (5.3 X 10^15) = 5.657 X 10^-8 m 
(Calculation source A.S. on Yahoo!)

6.5 × 10-7 m     5.657 X 10^-8 m 
This makes the red light larger in wavelength.
The wavelength of the unknown wave is less than the wavelength of red light.
Hope this helps, I really need some brainliest answers for next rank.

Answer 2

Answer:

The wavelength of the unknown wave is less than the wavelength of red light

Explanation:

The wavelength of the red light ,$=\lambda =6.5\times 10^{-7} m$

Frequency of the unknown wave = $\nu =5.3\times 10^{15} Hz$

Wavelength of the unknown wave = $\lambda '$

Speed of light = c

$\lambda '= \frac{c}{\nu }$

$\lambda '= \frac{3\times 10^8}{5.3\times 10^{15} s^{-1}}$

$=5.6604\times 10^{-8} m$

$\lambda > \lambda '$

The wavelength of the unknown wave is less than the wavelength of red light