Question

Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?

Answer 1

Hello!

First of all we solve for the slope as seen below.

$\frac{3+5}{-6+4} = -\frac{8}{2} = -4$

Our slope is -4.

Now we substitute a point from our equation into slope intercept form, along with the slope. Then we solve for b. We will use (-4,-5)

-5=-4(-4)+b
-5=16+b
b=-21

Our final equation is shown below.

y=-4x-21

I hope this helps!

Answer 2

The equation of line with slope m=-4 is,

$y=-4x-21$

We have given that the point J(-4,-5) and K(-6,3).

We have to find the value of b.

What is the formula for slope of two points ?

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{3-(-5)}{-4-(-6)}\\m=-\frac{8}{2} \\m=-4$

Therefore the slope is -4.

Next,we substitute a point from our equation into slope intercept form, Here we will use the point  (-4,-5)

$-5=-4(-4)+b\\-5=16+b\\b=-21$

Therefore, we get the equation of line with slope m=-4 is,

$y=-4x-21$

To learn more about the slope point form visit:

https://brainly.com/question/24907633