Question

The solution to this system of equations lies between the x-values -2 and -1.5. At which x-value are the two equations approximately equal? Y = 1/x+2 Y=x^2+2

Answer 1

Hello,
$\left \{ {{y= \dfrac{1}{x+2} } \atop {y=x^2+2}} \right. \\\\ \left \{ {{y= \dfrac{1}{x+2} } \atop {\dfrac{1}{x+2}=x^2+2}} \right. \\\\ \left \{ {{y= \dfrac{1}{x+2} } \atop {x+2= \dfrac{1}{x^2+2} }} \right. \\\\ \left \{ {{y= \dfrac{1}{x+2} } \atop {x= \dfrac{1}{x^2+2} -2}} \right.$
x=-1.81053571 and y= 5,27803957

Answer 2

Answer:

The solution to this system of equations is -1.811.

Step-by-step explanation:

The given system of equations is

$y=\frac{1}{x+2}$

$y=x^2+2$

Graph these function on a coordinate plane. The x-coordinate of intersection points of both functions are solutions of the given system of equations.

The graph of both functions is given below.

From the below graph it is clear that the intersection point of both the function is (-1.811,5.278).

Therefore the solution to this system of equations is -1.811.