Respuesta :
I first begin by dividing 13 by 6 to get 2.16666666667. I then multiple that number by 432 in^2 to get the answer : 936 in^2 for the larger solid.
The scale factor is given by:
[tex]k = 6/13 [/tex]
The relationship of the areas for this case is given by:
[tex]k ^ 2 = (6/13) ^ 2 [/tex]
Rewriting we have:
[tex]k ^ 2 = (6/13) ^ 2 k ^ 2 = 36/169[/tex]
The relation of volumes is:
[tex]k ^ 3 = V1 / V2 [/tex]
Where,
V1: small solid volume
V2: volume of the large solid
Clearing V2 we have:
[tex]V2 = V1 / k ^ 3 [/tex]
Substituting values:
[tex]V2 = 432 / (6/13) ^ 3 V2 = 4394 in ^ 3[/tex]
Answer:
The ratio of their corresponding areas is:
36/169
The volume of the larger solid is:
4394 in ^ 3
[tex]k = 6/13 [/tex]
The relationship of the areas for this case is given by:
[tex]k ^ 2 = (6/13) ^ 2 [/tex]
Rewriting we have:
[tex]k ^ 2 = (6/13) ^ 2 k ^ 2 = 36/169[/tex]
The relation of volumes is:
[tex]k ^ 3 = V1 / V2 [/tex]
Where,
V1: small solid volume
V2: volume of the large solid
Clearing V2 we have:
[tex]V2 = V1 / k ^ 3 [/tex]
Substituting values:
[tex]V2 = 432 / (6/13) ^ 3 V2 = 4394 in ^ 3[/tex]
Answer:
The ratio of their corresponding areas is:
36/169
The volume of the larger solid is:
4394 in ^ 3