Respuesta :
Answer:
" 6 must be factored from [tex]6x^2 + 18x[/tex] "
Step-by-step explanation:
We are given a equation as:
[tex]y=6x^2+18x+14[/tex]
On expressing the given equation in terms of [tex]y=a(x-h)^2+k[/tex]
where h, k are real numbers; we get our quadratic equation as:
[tex]6(x-\dfrac{3}{2})^2+\dfrac{1}{2}[/tex]
Here on comparing our equation with [tex]y=a(x-h)^2+k[/tex] we have :
[tex]h=\dfrac{3}{2}[/tex] and [tex]k=\frac{1}{2}[/tex].
This means that we have to first factor out '6' from the term [tex]6x^2+18x[/tex]