Question

Find the perimeter of the shape below:

Answer 1

There are four lines: KJ, JM, ML, LK.
To find the length of each line, use the Pythagorean Theorem.
$a = \sqrt{ {b}^{2} + {c}^{2} }$
KJ: 2 units vertical, 2 units horizontal.
$a = \sqrt{ {2}^{2} + {2}^{2} } \\ = \sqrt{4 + 4} \\ = \sqrt{8}$
JM: 1 unit vertical, 2 units horizontal.
$a = \sqrt{ {1}^{2} + {2}^{2} } \\ = \sqrt{1 + 4} \\ = \sqrt{5}$
ML: 2 units vertical, 2 units horizontal.
$a = \sqrt{8}$
LK: 5 units vertical, 2 units horizontal.
$a = \sqrt{ {5}^{2} + {2}^{2} } \\ = \sqrt{25 + 4} \\ = \sqrt{29}$
Therefore, the perimeter is
$\sqrt{8} + \sqrt{5} + \sqrt{8} + \sqrt{29}$
I don't know how to simplify that further

Answer 2

Perimeter is the sum of the length of the sides used to make the given figure. The perimeter of the given figure is 13.278 units.

What is the perimeter?

Perimeter is the sum of the length of the sides used to make the given figure.

The length of the line segment on a coordinate system is calculated using the formula,

Length = √[(Vertical length)² + (Horizontal length)²]

Now, The length of different sides can be written as,

LM = √(2² + 2²) = 2√2 units

JM = √(1² + 2²) = √5 units

KJ = √(2² + 2²) = 2√2 units

KL = √(5² + 2²) = √29 units

Further, the perimeter of the given figure is,

Perimeter = 2√2 units + √5 units + √29 units + 2√2 units

                = 13.278 units

Hence, the perimeter of the given figure is 13.278 units.

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