Respuesta :

(3x)(9x^2+1) is factored completely since you cannot factor a sum of squares.

Answer:

Option C. is the correct option.

Step-by-step explanation:

We will try to factorize each option

a) [tex]4(4x^{4}-1)[/tex]

= 4[(2x²)² - 1] = 4[(2x²-1)(2x²+1)]  [since (a²- b²)=(a-b)(a+b)]

b) 2x(y³-4y²+5y)

= 2xy(y² - 4y + 5)

c) 3x(9x²+ 1) It is in the factored form.We can not factorize it further.

d) 5x²- 17x + 14

= 5x²- 10x - 7x + 14 = 5x(x - 2) - 7(x -2) = (5x - 7)(x - 2)