Answer:
The correct option is 3.
Step-by-step explanation:
If four coins are flipping, then the total possible outcomes are
S = {HHHH, HHHT, HHTH, HHTT ,HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT, TTHH, TTHT, TTTH, TTTT} = 16
At least two coins landing on heads, it means 2 or more coins landing on heads.
A = {HHHH, HHHT, HHTH, HHTT ,HTHH, HTHT, HTTH , THHH, THHT, THTH, TTHH} = 11.
The probability of at least two coins landing on heads is
[tex]Probability=\frac{\text{Possible outcomes of at least two coins landing on heads }}{\text{Total possible outcomes}}[/tex]
[tex]Probability=\frac{11}{16}[/tex]
Therefore the correct option is 3.
