Question

A carbon-12 atom has a mass defect of 0.09564 amu. Which setup is used to calculate nuclear binding energy?
a. 0.09564 amu x (1.6606 x 10–27 kg)/amu x (3.0 x 108)2
b. 0.09564 amu x 1 amu/(1.6606 x 10–27 kg) x (3.0 x 108)2C. 0.09564 amu x (3.0 x 108)2D. 0.09564 amu x (1.6606 x 10–27 kg)/amu x (3.0 x 108)

Answer 1

Answer:

A

Explanation:

Got it right on the instruction on Edge.

Answer 2

A carbon-12 atom has a mass defect of 0.09564 amu then nuclear binding energy will be calculated as (0.09564amu × 1.6×10⁻²⁷kg/amu) × (3×10⁸m/s)².

How do we calculate nuclear binding energy?

Nuclear binding energy of any atom will be calculated as:

E = mc², where

m = mass of substance in kg

c = speed of light = 3×10⁸m/s

Given that, mass defect = 0.09564 amu

We know that in 1 amu = 1.6 × 10⁻²⁷ kg of substance is present

Mass of Carbon-12 atom =  0.09564amu × 1.6×10⁻²⁷ kg/amu

On putting these values on the above equation, we get

E = (0.09564amu × 1.6×10⁻²⁷kg/amu) × (3×10⁸m/s)²

Hence correct option is (0.09564amu × 1.6×10⁻²⁷kg/amu) × (3×10⁸m/s)².

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