Question

What is the approximate value of q in the equation below? q+log2 6 = 2q+2?

Answer 1

Subtract q+2 from both sides of the equation and you get
  log2(6) -2 = q
  q ≈ 0.5849625

Answer 2

$q +log_{2}6 = 2q +2 \\ \\ log_{2}6 = q +2 \\ \\ \frac{ln6}{ln2} =q+2 \\ \\q= \frac{ln6}{ln2} - 2 \\ \\ q=0.5850 (approximately)$