Question

Given: F(x) = 3x 2 + 1, G(x) = 2x - 1, H(x) = x


FG =


4x²

12x²+4

12x²-12x+4

Answer 1

$f(x) = {3x}^{2} + 1 \\ g(x) = 2x - 1$
FG(x) = you insert g(x) into f(x)
So,
$3(2x - 1) {}^{2} + 1 \\ = 3(4x {}^{2} - 4x + 1) + 1 \\ = 12x {}^{2} - 12x + 3 + 1 \\ = 12 {x}^{2} - 12x + 4$
So the answer is the bottom one