To solve this problem you must apply the proccedure shown below:
1. You have the following information given in the problem above:
- The first term of a geometric series is 3.
- The sum of the first term and the second term is 15.
2. Keeping this on mind, you must find the common ratio, as following:
[tex]3+3r=15 \\ 3r=12 \\ r=4[/tex]
3. Now, multiply each term by the common ratio, and you will obtain:
[tex]3,12,48,192,768,3072[/tex]
4. The sum of the first six terms is:
[tex]3+12+48+192+768+3072=4095[/tex]
The answer is: [tex]4095
[/tex]