Respuesta :
There are some missing data in the text of the problem. I've found them online:
a) coefficient of friction dry steel piston - steel cilinder: 0.3
b) coefficient of friction with oil in between the surfaces: 0.03
Solution:
a) The force F applied by the person (300 N) must be at least equal to the frictional force, given by:
[tex]F_f = \mu N[/tex]
where [tex]\mu[/tex] is the coefficient of friction, while N is the normal force. So we have:
[tex]F=\mu N[/tex]
since we know that F=300 N and [tex]\mu=0.3[/tex], we can find N, the magnitude of the normal force:
[tex]N= \frac{F}{\mu}= \frac{300 N}{0.3}=1000 N [/tex]
b) The problem is identical to that of the first part; however, this time the coefficienct of friction is [tex]\mu=0.03[/tex] due to the presence of the oil. Therefore, we have:
[tex]N= \frac{F}{\mu}= \frac{300 N}{0.03}=10000 N [/tex]
a) coefficient of friction dry steel piston - steel cilinder: 0.3
b) coefficient of friction with oil in between the surfaces: 0.03
Solution:
a) The force F applied by the person (300 N) must be at least equal to the frictional force, given by:
[tex]F_f = \mu N[/tex]
where [tex]\mu[/tex] is the coefficient of friction, while N is the normal force. So we have:
[tex]F=\mu N[/tex]
since we know that F=300 N and [tex]\mu=0.3[/tex], we can find N, the magnitude of the normal force:
[tex]N= \frac{F}{\mu}= \frac{300 N}{0.3}=1000 N [/tex]
b) The problem is identical to that of the first part; however, this time the coefficienct of friction is [tex]\mu=0.03[/tex] due to the presence of the oil. Therefore, we have:
[tex]N= \frac{F}{\mu}= \frac{300 N}{0.03}=10000 N [/tex]
A) The magnitude of the normal force between the piston and cylinder is : 1000 N
B) The magnitude of the force exerted when parts are oiled = 10000 N
Given data :
Force exerted by physics major = 300 n
coefficient of friction of dry steel cylinder ( μ ) = 0.3 ( found online )
coefficient of friction with oil in between ( μ ) = 0.03 ( found online )
A) Determine the magnitude of normal force
Force applied ( Fa ) = frictional force ( μ N )
therefore :
N = Fa / μ
where μ = 0.3
magnitude of normal force ( N ) = 300 / 0.3
= 1000 N
B) Determine the magnitude of force when oil is applied
N = Fa / μ
= 300 / 0.03
= 10000 N
Hence we can conclude that The magnitude of the normal force between the piston and cylinder is : 1000 N and The magnitude of the force exerted when parts are oiled = 10000 N
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