Question

a bicycle rider increases his speed from 15 m/s to 5 m/s in 10 seconds. what is his rate of acceleration

Answer 1

a = change in velocity divided by change in time
a = v/t
= 15 - 5 / 10 - 0 = 10 / 10 = 1 m/s^2

Answer 2

The rate of acceleration of a bicycle rider is 1 m/s^2.

What is rate of acceleration?

Acceleration is the rate at which velocity (speed) is changing. Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt.

For the given situation,

A bicycle rider increases his speed from 15 m/s to 5 m/s.

⇒ Δv = $15-5$

⇒  Δv = $10 m/s$

Change in time, Δt = $10 seconds$

The formula of rate of acceleration is

a = Δv/Δt

On substituting the above values,

⇒ $a=\frac{10}{10}$

⇒ $a=1$

Hence we can conclude that the rate of acceleration of a bicycle rider is 1 m/s^2.

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