Respuesta :
I think the answer would be Ionic sodium phosphate (Na3PO4) because it has the greatest boiling point elevation.
Answer: ionic sodium phosphate [tex](Na_3PO_4)[/tex]
Explanation:
The formula used:
[tex]\Delta T_b=i\times k_b\times m[/tex]
[tex]\Delta T_b[/tex]= change in boiling point
i = Van'T Hoff factor
[tex]k_b[/tex] = boiling point constant
m = molality
1. For [tex]LiCl[/tex]
[tex]LiCl\rightarrow Li^{+}+Cl^{-}[/tex]
i= 2 as it is ionic and dissociate to give 2 ions.
2. For [tex]NaCl[/tex]
[tex]NaCl\rightarrow Na^{+}+Cl^{-}[/tex]
i= 2 as it is ionic and dissociate to give 2 ions.
3. For [tex]C_{12}H_{22}O_{11}[/tex]
, i= 1 as it is a non electrolyte and does not dissociate.
4. For [tex]Na_3PO_{4}[/tex]
[tex]Na_3PO_4\rightarrow 3Na^{+}+PO_4^{3-}[/tex]
, i= 4 as it is ionic and dissociate to give 4 ions.
5. For [tex]MgBr_{2}[/tex]
[tex]MgBr_2\rightarrow Mg^{2+}+2Br^-[/tex]
, i= 3 as it is ionic and dissociate to give 3 ions.
Thus as vant hoff factor is highest for [tex]Na_3PO_{4}[/tex] , the boiling point will be raised most.