Question

The product of ab=1200. a is an integer and b is an odd integer. What is the largest possible value of b

Answer 1

Answer:

Largest possible value of b is:

75

Step-by-step explanation:

we are given that:

ab=1200

where a is an integer and b is an odd integer.

we know that product of odd numbers is always odd.

Now, 1200= 12×100

                = 2×6×10×10

               =2×2×3×2×5×2×5

It cannot be factorized further

Now, considering the product of all odd numbers

=3×5×5

=75

Now, if we multiply any other remaining number from the factorization of 1200, we will get a even number

Hence, The largest possible value of b is:

75

Answer 2

Answer:

75

Step-by-step explanation:

Factoring out the highest power of 2 from 1200, we find that $1200=2^4\cdot75$.  Therefore, the largest possible value of $b$ is $\boxed{75}$.

Hope this helped! :)