Question

What is the simplest form of the expression below? 2x^2 − 10x − 28 /6x × 6/ x − 7

Answer 1

$\dfrac{2x^2-10x-28}{6x}\cdot\dfrac{6}{x-7}=\dfrac{2x^2-14x+4x-28}{x}\cdot\dfrac{1}{x-7}\\\\=\dfrac{2x(x-7)+4(x-7)}{x}\cdot\dfrac{1}{x-7}=\dfrac{(x-7)(2x+4)}{x}\cdot\dfrac{1}{x-7}\\\\=\dfrac{2x+4}{x}$