select the correct answer from each drop down menu
options
odd positive
even negative
![select the correct answer from each drop down menu options odd positive even negative class=](https://us-static.z-dn.net/files/d01/73401dd4d9f531a96aab911060461e94.png)
Answer: The graph is even negative.
Explanation: Since, By the definition of end behavior of a function If for a function f(x), [tex]f(x)\rightarrow-\infty[/tex] as [tex]x\rightarrow-\infty[/tex]
And, [tex]f(x)\rightarrow-\infty[/tex] as [tex]x\rightarrow+\infty[/tex]
then the function f(x) is a negative function with even leading coefficient.
Here, we can see that in the given graph the function shows the above behavior.
Therefore, it has even negative function.