Solve the system of equations.

y = 3x + 2
y = x^2 – 4x + 2

A. (0, –2) and (–7, –23)
B. (–7, –23) and (0, 2)
C. (–7, 23) and (0, –2)
D. (0, 2) and (7, 23)

Respuesta :

When you solve a system of equations you are determining where the curves intersect in a coordinate plane.  These places of intersection share the exact same x and y points.  Since both equations above are already solved for y, and since the y values for each will be the same, let's set them equal to each other and solve for x.  [tex]3x+2= x^{2} -4x+2[/tex].  The way to solve for x is to combine like terms, set the resulting polynomial equal to 0, and factor to find x.  Doing that gives us [tex] x^{2} -7x=0[/tex].  We can factor a common x out of those terms to get 0 = x(x-7).  By the Zero Product Property theorem, x = 0 or x-7 = 0.  So x = 0 and x = 7.  Sub those x values back in to solve for y.  y = 3(0)+2 and y = 2.  So one of our coordinates is (0, 2).  y = 3(7)+2 so y = 23.  The other coordinate is (7, 23).  Those choices are found together in D above.

Answer:

D. (0, 2) and (7, 23)

Step-by-step explanation:

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