Question

what is slope of a line that passes (-12,15)and(0,4)?

Answer 1

Given points:
(x₁,y₁) = (-12,15)
(x₂,y₂) = (0,4)

Use slope formula
$m= \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$
$m= \dfrac{4-15}{0-(-12)}$
$m= \dfrac{-11}{0+12}$
$m= -\dfrac{11}{12}$

The slope of the line is equal to -11/12

Answer 2

Hi there!

• ( x₁ , y₁ ) = ( -12 , 15 )
• ( x₂ , y₂ ) = ( 0 , 4 )

by Slope formula :-

m = $\dfrac {y_{2} - y_{1} }{x_{2} - x_{1} }$

=> m = $\dfrac {4 - 15}{0 - (-12)}$

=> m = $\dfrac {-11}{0 + 12}$

=> m = $\dfrac {-11}{12}$

Hence,
The slope of th' line is $\dfrac {-11}{12}$

~ Hope it helps!