is the relationship between the variables in this table a direct variation, an inverse variation or neither. if it is a direct or inverse variation, write a function to model it. x: 2, 4, 6, 8 y: 1/3, 1/6, 1/9, 1/12
For this case we have that the relationship is inverse. Therefore, we have a function of the form: [tex]y = \frac{k}{x} [/tex] We must find the value of k. For this, we use any ordered pair, such as: [tex](x, y) = (2, 1/3)
[/tex] Substituting values: [tex] \frac{1}{3} = \frac{k}{2} [/tex] Clearing k we have: [tex]k = \frac{2}{3} [/tex] Then, the function is: [tex]y = \frac{2}{3x} [/tex] Answer: The relationship between the variables in this table is an inverse variation. A function to model is: [tex]y = \frac{2}{3x} [/tex]