is the relationship between the variables in this table a direct variation, an inverse variation or neither. if it is a direct or inverse variation, write a function to model it. x: 2, 4, 6, 8 y: 1/3, 1/6, 1/9, 1/12

Respuesta :

For this case we have that the relationship is inverse.
 Therefore, we have a function of the form:
 [tex]y = \frac{k}{x} [/tex]
 We must find the value of k.
 For this, we use any ordered pair, such as:
 [tex](x, y) = (2, 1/3) [/tex]
 Substituting values:
 [tex] \frac{1}{3} = \frac{k}{2} [/tex]
 Clearing k we have:
 [tex]k = \frac{2}{3} [/tex]
 Then, the function is:
 [tex]y = \frac{2}{3x} [/tex]
 Answer:
 
The relationship between the variables in this table is an inverse variation.
 
A function to model is:
 
[tex]y = \frac{2}{3x} [/tex]
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