Question

Given that mc006-1.jpg, what is the value of mc006-2.jpg, for mc006-3.jpg?

Answer 1

If sin theta = 21/29 and we know that theta is in Quadrant I, then

by the Pyth. Theorem,  21^2 + (adjacent side)^2 = 29^2.

Thus, adj^2 = 29^2 - 21^2, or     adj^2 = 841 - 441  =   400.

Then adj = plus or minus 20.    What is cos theta if theta is in Q I? 

cos theta = adj / hyp  =  20/29

Answer 2

Applying a trigonometric relation, it is found that $\cos{\theta} = \frac{20}{29}$

The sine and cosine of an angle $\theta$ are related by the following equation:

$\sin^2{\theta} + \cos^{2}{\theta} = 1$

In this problem, we have that:

$\sin{\theta} = \frac{21}{29}$

Hence:

$\sin^2{\theta} + \cos^{2}{\theta} = 1$

$\cos^{2}{\theta} = 1 - \sin^2{\theta}$

$\cos^{2}{\theta} = 1 - \left(\frac{21}{29}\right)^2

[tex]\cos^{2}{\theta} = \frac{400}{29^2}$

$\cos{\theta} = \pm \sqrt{\frac{400}{29^2}}$

First quadrant, hence, the cosine is positive, and:

$\cos{\theta} = \frac{20}{29}$

For more on trigonometric relations, you can check https://brainly.com/question/24680641