[tex]\bf \qquad \textit{Amount for Exponential Decay}
\\\\
A=P(1 - r)^t\qquad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &250000\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
t=\textit{elapsed time}\to &3\\
\end{cases}
\\\\\\
A=250000(1-0.06)^3\implies A=250000(0.94)^3\implies A=207646[/tex]