Question

What volume of 0.330 M Na2co3 (106g/mol) solution contains 32.7 of Na2co3?

Answer 1

Hello!

We having the following data:

V (volume) = ? (in L)
M (molar concentration) = 0.330 M (Mol/L)
MM (Molar Mass of Na2CO3) = 106 g/mol
m (mass of the solute) = 32.7 g

We apply the data to the molar formula or molar concentration, see:

$M = \dfrac{m}{MM*V}$

$0.330 = \dfrac{32.7}{106*V}$

$0.330*106*V = 32.7$

$34.98V = 32.7$

$V = \dfrac{32.7}{34.98}$

$\boxed{\boxed{V \approx 0.93\:L}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR!