Given:
(x₁,y₁) = (1,5)
(x₂,y₂) = (3,11)
Solution:
First, determine the slope of the line with slope formula
m = [tex] \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
m = [tex] \dfrac{11-5}{3-1}[/tex]
m = [tex] \dfrac{6}{2}[/tex]
m = 3
Second, substitute the value of the slope m and one of the points to the formula of line equation below
y - y₁ = m(x - x₁)
y - 5 = 3(x - 1)
y - 5 = 3x - 3
3x - 3 = y - 5
3x - y = -5 + 3
3x - y = -2
This is standard form of a line
