Question

When iron rusts in air iron3 oxide is produced. How many moles of oxygen react with 28.0 mol of iron in the rusting reaction 4fe(s) 3o2(g) 2fe2o3(s)

Answer 1

This the balanced equation based on the question $4Fe + 3O_2 -\ \textgreater \ 2Fe_2O_3$.

We then proceed with the following calculations

$28.0molFe*(\frac {3molO_2}{4mol Fe})= 21molO_2$

The answer is $21molO_2$ is produced.