Answer:The correct answer is option B.
Explanation:
Mass of surcose dissolved = 50.0 g
volume of water = 1 L
Molarity=[tex]\frac{\text{Mass of sucrose}}{\text{molar mass of sucrose}\times \text{volume of solvent in L}}[/tex]
[tex]Molarity=\frac{50.0 g}{342.3 g/mol\times 1 L}=0.1460 mol/L[/tex]
Hence ,the correct answer is option B.