The equation is 2Na3N = 2Na + 3N2
100.0g Na3N(1mol Na3N / 65.02g Na3N) (3mol N2 / 2mol Na3N) (28.02g N2/1mol N2)
[tex]100.0g Na3N * (\frac{1mol Na3N}{65.02 Na3N}) * ( \frac{3mol N2}{2mol Na3N} ) * ( \frac{28.02g N2}{1mol N2} ) = 64.6 g N2[/tex]
The answer is 64.6 grams of N2 are formed or 64.6g N2