Question

A cup sits on a table. Due to its position, the potential energy of the cup is 3.00 joules. Ignoring frictional effects, if the cup falls off the table, how much kinetic energy will it have when it is halfway to the floor? 3.00 J 1.50 J 0.00 J cannot be determined without knowing the mass and the height of the cups

Answer 1

Due to conservation of energy, half way the potential energy will be 1.5J so the remaining 1.5J is kinetic energy.

Answer 2

Answer:

KE = 1.50 J

Explanation:

As we know that there is no frictional force here while it is dropped down then in that case we can say that total mechanical energy will remains conserved in it

So here we can say that

$KE + PE = constant$

initially when it is at top the total mechanical energy is in the form of potential energy which is given as 3.00 J

now when it is dropped down by half of the distance then half of the potential energy will remain in it.

So we can say that half of the potential energy will convert into kinetic energy in it

So here we have

$KE = PE = 1.50 J$