Question

Factor completely, then place the answer in the proper location on the grid. 6x ^2 - 3x - 30

Answer 1

Factor out the GCF first
3(2x² - x - 10)
3(2x - 5)(x + 2)

Answer 2

Answer:

3(2x-5)(x+2)

Step-by-step explanation:

Given is an algebraic expression in x in degree 2 as

$6x ^2 - 3x - 30$

and we have to factor completely.

Seeing the coefficients we find that GCF is 3.

So 3 is a factor

Given expression =

$3(2x ^2 - x - 10)$

Inside product of last term and coefficient of I term is 20.

5x4 =20 and difference = -1 = the middle term

Hence

$3(2x ^2 - x - 10)\\=3[2x^2-5x+4x-10]\\=3(2x-5)(x+2)$