Question

What is the domain of the following parabola? (5 points) u-shaped graph that opens down with a vertex of 2, 3 x ≥ 2 x ≤ −1 y ≤ 3 All real numbers

Answer 1

all real numbers would be the correct answer for this question.

Answer 2

It is known that the parabola is U-shaped, so it is a function, and that its vertex is (2, 3). The correct option is d: All real numbers.

What is the vertex form of a quadratic equation?

If a quadratic equation is written in the form

$y=a(x-h)^2 + k$

then it is called to be in vertex form. It is called so because when you plot this equation's graph, you will see vertex point(peak point) is on (h,k)

This point (h,k) is called the vertex of the parabola that the quadratic equation represents.

For a function f(x), the domain is the set of all the possible values of x that we can input in that function.

To find the domain of a function is:

First, consider that the domain is the set of all real numbers.

Then, look at the restrictions implied:

f(x) = 4   if x > 3

Here the domain of the function is implied.

In this case, we have a quadratic function:

$y = ax^2 + bx + c$

Her, we do not have any restrictions.

It is known that the parabola is U-shaped, so it is a function, and that its vertex is (2, 3).

Then we can conclude that the domain of this function is the set of all real numbers.

Thus, The correct option is d: All real numbers.

Learn more about the vertex form of a quadratic equation here:

https://brainly.com/question/9912128

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