Question

what is the value of x to the nearest tenth
3.6
5.8
11.5
14.3

Answer 1

I'm not sure but I think it's 11.5.

Answer 2

Answer:

C. 11.5

Step-by-step explanation:

We can see from our given diagram that we have a right triangle inside our circle, so we will use Pythagorean theorem to find the value of x.

Since length of segment is x and side length with measure 3 is perpendicular to x, so side length of right triangle will be x/2.

$(\frac{x}{2})^2+3^2=6.2^2$

$\frac{x^2}{4}+9=42.25$

$\frac{x^2}{4}+\frac{9*4}{4}=42.25$  

$\frac{x^2}{4}+\frac{36}{4}=42.25$

$\frac{x^2+36}{4}=42.25$

Multiply both sides of equation by 4.

$4*\frac{x^2+36}{4}=4*42.25$

$x^2+36=169$  

$x^2+36-36=169-36$  

$x^2=133$  

Let us take square root of both sides of our equation.

$\sqrt{x^2}=\sqrt{133}$  

$x=11.5325625946707959\approx 11.5$    

Therefore, the value of x is 11.5 and option C is the correct choice.