Question

If the letters in the word poker are rearranged, what is the probability that the word will begin with the letter k and end with the letter p?

Answer 1

The probability is 6/120 or 1/20, which can be expressed as a percentage of 5%.

You can find this by first deciding how many possibilities there are. With a number of items being arranged in a set, the easiest way to solve this is by using the factorial function on your calculator (the button that looks like "!"). It denotes That number by all of the integers lower than it down to 1 multiplied together. 

So since there are 5 letters in poker, we would use 5! or written out:
1*2*3*4*5 = 120. 

Then we would have to find all of the options that start with k and end with p, of which there are exactly 6. 

koerp
korep
kreop
kroep
kerop
keorp

So then we divide the number of possibles by the total number of options. 

Answer 2

The probability that the word will begin with the letter K and end with the letter P is 1/20.

What is probability?

Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1. Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.

Given

The word POKER

The total event will be given by

$\rm Total \ event = 5! \\\\Total \ event = 5* 4*3*2*1\\\\Total \ event = 120$

If the letter begins with the letter K and ends with the letter P. Then the favorable will be given by

$\rm Favorable \ event = 3! \\\\Favorable \ event = 3*2*1\\\\Favorable \ event = 6$

Then probability will be

$\rm P = \dfrac{6}{120}\\\\P = \dfrac{1}{20}$

Thus, the probability that the word will begin with the letter K and end with the letter P is 1/20.

More about the probability link is given below.

https://brainly.com/question/795909