Question

In the right triangle, AC = BC = 2. What is AB?

Answer 1

Short Answer: x = 2*sqrt(2)
The Pythagorean Theorem states that 
a^2 + b^2 = c^2

Givens
a = 2
b = 2
c = ???

Sub and solve
2^2 + 2^2 = c^2
c^2 = 4 + 4
c^2 = 8                                  Take the sqrt of both sides of the equation
sqrt(c^2) = sqrt(8)                 Express 8 in it's prime factor form.
sqrt(c^2) = sqrt(2 * 2 * 2)

The rule about square roots is 
If you have a pair of prime factors under the root sign, you take out one of the prime factors and throw the other one away.

sqrt(c^2) = 2*sqr(2)

Answer x = 2*sqrt(2)

Answer 2

Formula for hypotenuse:
$\sqrt{ a^{2} + b^{2} }=c$

a would be AC 
b would be CB
c is AB

$\sqrt{ 2^{2} +2^{2} }$
$\sqrt{4+4}$
$\sqrt{8}$

It is $\sqrt{8}$ or $2\sqrt{2}$ or about 2.83