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30-05-2018
Mathematics

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please help asap 30 pts

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30-05-2018

[tex]\dfrac{x^2+4x-5}{1-x}=\dfrac{x^2+5x-x-5}{-(x-1)}=\dfrac{x(x+5)-1(x+5)}{-(x-1)}\\\\=\dfrac{(x+5)(x-1)}{-(x-1)}=-(x+5)\\\\\boxed{Answer:-x-5}[/tex]

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