Question

if CG = 10, AC = 8, BC = 5 find DC
4
2√(10)
1.5

Answer 1

For secants from a common external point, the product of near and far lengths to the circle is a constant.
   BC·AC = DC·GC
   5·8 = DC°10
   DC = 40/10
   DC = 4

The appropriate choice is the first one.
   4

Answer 2

Answer: 4

Step-by-step explanation:

Yup 4 is the correct answer. Just got it right