Question

f(x)=x²-1 and g(x)=x-1 what is the value of (f/g)(x)

Answer 1

$f(x)=x^2-1=x^2-1^2=(x-1)(x+1);\ g(x)=x-1\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{x^2-1}{x-1}=\dfrac{(x-1)(x+1)}{x-1}=x+1\\\\The\ domain:\ x\neq1$

$Used:\\a^2-b^2=(a-b)(a+b)$