Question

What is the velocity of a 500-kilogram elevator that has 4,000 joules of energy?

Answer 1

The Energy is Kinetic Energy.

Kinetic Energy = 1/2*mv²,  Where m is mass in kg, v is velocity in m/s

Energy is 4000 Joules,  v = ?
mass, m = 500kg

1/2*mv² = E

1/2*500*v² = 4000

v² = (2*4000) / (500)     Using a calculator

v² = 16     Taking square root

v = √16

v = 4 

Velocity  of object is 4 m/s.

Answer 2

The velocity of a 500-kilogram elevator that has 4,000 joules of energy is 4m/s.

KINETIC ENERGY:

• The kinetic energy of a substance is its energy during motion. It can be calculated using the formula below:

K.E = ½m.v²

Where;

m = mass of the elevator (kg)

v = velocity of the elevator (m/s)

• According to this question, the energy of the 500kg elevator is given as 4,000 joules, hence, the velocity can be calculated as follows:

V = √K.E × 2/m

V = √4000 × 2/500

V = √8000/500

V = √16

V = 4m/s

• Therefore, the velocity of a 500-kilogram elevator that has 4,000 joules of energy is 4m/s.

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