What is the interquartile range of this data set?

1, 5, 27, 29, 34, 37, 48, 61, 72, 84, 96
A. 45
B. 37
C. 10
D. 64

Respuesta :

Answer: Choice A) 45

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The given set of values is 
A = {1, 5, 27, 29, 34, 37, 48, 61, 72, 84, 96}
The median of this set is 37. Five values are below it; five values are above it. It is the middle most value.

Let
L = {1, 5, 27, 29, 34}
be the lower set of values smaller than the median. We see that the median of set L is 27. So Q1 = 27

Let
U = {48, 61, 72, 84, 96}
which is composed of all the values above the median
The median of the upper set of values is 72. So Q3 = 72

Subtract the first and third quartile values to get the interquartile range (IQR)
IQR = Q3 - Q1
IQR = 72 - 27
IQR = 45

Answer: 45

Step-by-step explanation:

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