Question

An experiment consists of randomly selecting a ball from a box, replacing it and then selecting another ball. The box contains 8 pink balls and 6 brown balls. What is the probability of selecting a brown ball and then a pink ball?

Answer 1

P(selecting a brown ball first) =  6/14 = 3/7
P(selecting a pink ball) = 8/14 = 4/7

Probability of selecting a brown then a pink = 3/7 * 4/7 = 12/49 (answer)

Answer 2

Hence if experiment consists of randomly selecting a ball from a box, replacing it and then selecting another ball. The box contains 8 pink balls and 6 brown balls, then  the probability of selecting a brown ball and then a pink ball is 12/49

What is probability ?

Probability is chances of occurring of an event.

Here given that experiment consists of randomly selecting a ball from a box, replacing it and then selecting another ball. The box contains 8 pink balls and 6 brown balls.

Now probability of getting  brown ball = 6/14=3/7

Probability of getting pink ball =8/14=4/7

Now  probability of selecting a brown ball and then a pink ball can be calculated as

P(a brown ball and then a pink ball)=P(Brown)P(pink)

$=\frac{3}{7} \times \frac{4}{7}$

=12/49

Hence if experiment consists of randomly selecting a ball from a box, replacing it and then selecting another ball. The box contains 8 pink balls and 6 brown balls, then  the probability of selecting a brown ball and then a pink ball is 12/49

To learn more about probability visit : brainly.com/question/24756209