Question

Given the reaction that occurs in an electrochemical cell: Zn(s) + CuSO4(aq) --> ZnSO4(aq) + Cu(s) During this reaction, the oxidation number of Zn changes from

Answer 1

Zn⁰(s) + CuSO4(aq) --> Zn²⁺SO4²⁻(aq) + Cu(s)

Zn⁰ --- in free elements oxidation number is 0.
Zn²⁺SO4²⁻ ---- ionic compound , it has ion Zn²⁺, so oxidation number here is +2.
The oxidation number of Zn changes from 0 to +2.

Answer 2

The reaction that occurs in an electrochemical cell:

$Zn(s) + CuSO_4(aq)$ --> $ZnSO_4(aq) + Cu(s)$

During this reaction, the oxidation number of Zn changes from 0 to +2.

What is an electrochemical cell?

An electrochemical cell is a device that can produce an electrical current from a chemical reaction and/or use electrical energy to produce a chemical reaction.

Zn⁰(s) + CuSO4(aq) --> Zn²⁺SO4²⁻(aq) + Cu(s)

Zn⁰ is in free elements oxidation number is 0.

Zn²⁺SO4²⁻ is an ionic compound, so oxidation number of Zn²⁺ here is +2.

Hence, the oxidation number of Zn changes from 0 to +2.

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