Question

If an ore is 32.4% ti by mass, what is the mass of ore that contains 200. g of ti?

Answer 1

Correct Answer: Mass of ore that contains 200 g of Ti is 617.28 g.

Reason:
Given: Ore contains 32.4% Ti by mass. 
It implies that, 100 g of ore ≡ 32.4 g of Ti
Therefore,              x g of ore   ≡ 200 g of Ti

Thus, x = $\frac{100X200}{32.4} = 617.28 g$

Hence, mass of ore that contains 200 g of Ti is 617.28 g.