Question

PLEASE ANSWER + BRAINLIEST!!

Factor completely.

2n^2 - 11n + 14 =

3v^2 - 8v - 16 =

Answer 1

I'd like to see some of your own efforts here.  This is the third time you've posted two "factor completelyl" problems, without sharing what you've already done.

3v^2 - 8v - 16 cannot be reduced.  Thus, your best choice to find roots is to apply the quadratic formula:

         8 plus or minus sqrt( 64-4(3)(-16) )
v = ---------------------------------------------------
                                2(3)
        8 plus or minus sqrt( 64 + 192 ) 
   = ---------------------------------------------
                                 6
         8 plus or minus sqrt(256)
    = -------------------------------------
                             6

     = 8 + 16, all divided by 6, or    8 - 16, all divided by 6

     = 4 or -8/6, or 4 or -4/3.

The factors are (v-4) and (v + 4/3).

Answer 2

$2n^2-11n+14=2n^2-4n-7n+14=2n(n-2)-7(n-2)\\\\=(n-2)(2n-7)=2(n-2)(n-3.5)$


$3v^2-8v-16=3v^2-12v+4v-16=3v(v-4)+4(v-4)\\\\=(v-4)(3v+4)=3(v-4)\left(v+\dfrac{4}{3}\right)$