Respuesta :
We can determine the number of solutions from the slope intercept form of the equations.
Slope intercept form of equation 1 is:
[tex]y=- \frac{1}{4}x+3/4 [/tex]
Slope intercept form of second equation is:
[tex]y=- \frac{1}{4}x+ \frac{9}{12} \\ \\ y= - \frac{1}{4}x+ \frac{3}{4} [/tex]
The slope and the y-intercept of both equations are the same. This means, the two lines are lying over each other and hence they infinite number of solutions.
So, the correct answer is option C
Slope intercept form of equation 1 is:
[tex]y=- \frac{1}{4}x+3/4 [/tex]
Slope intercept form of second equation is:
[tex]y=- \frac{1}{4}x+ \frac{9}{12} \\ \\ y= - \frac{1}{4}x+ \frac{3}{4} [/tex]
The slope and the y-intercept of both equations are the same. This means, the two lines are lying over each other and hence they infinite number of solutions.
So, the correct answer is option C
The equation no solution. This is because the lines are parallel.
The general equaltion of a line is,
Y=mX+c, where m is the gradient and c is the Y-intercept.
For the first equation,
4x + 16y = 12
16y=-4x+12
y=(-1/4)x+12/16
gradient =-1/4
For the second equation, Y = (-1/4)x +9/12, the gradient = -1/4
If the gradients are equation then, the lines do not meet hence no solutions.
The general equaltion of a line is,
Y=mX+c, where m is the gradient and c is the Y-intercept.
For the first equation,
4x + 16y = 12
16y=-4x+12
y=(-1/4)x+12/16
gradient =-1/4
For the second equation, Y = (-1/4)x +9/12, the gradient = -1/4
If the gradients are equation then, the lines do not meet hence no solutions.